Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:
- The distance to go between airports A and C is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.
In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C
Let's use the Pythagoras' theorem to find the distance traveled
R = [tex]\sqrt{x^2 +y^2}[/tex]
R = 373.6 10³ m
They indicate the average speed for which we can use the uniform motion ratio
v = [tex]\frac{\Delta y }{t}[/tex]
t = [tex]\frac{\Delta y}{v}[/tex]
They ask for the time in in from airport A to B, we calculate
t = 360 10³/170
t = 2.117 10³ s
In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:
- The distance to go between airports A and C B is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Learn more here: brainly.com/question/15074838

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.