Answered

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I round a number to 1 decimal place, which increases the number by 25%. What is the largest value this original number could have been?

Sagot :

DefBrainly

Answer:

0

Step-by-step explanation:

[tex]25\% = \frac{25}{100} = 0.25 = 0.3 = 0[/tex]

The largest value the original number could have been is; 0.16.

     When we round a number to one decimal place, it means that if the number in the second decimal place is equal to or greater than 5, we make it zero and add 1 to the number in the first decimal place.

    In contrast, if the number in the second decimal place is less than 5, we make it zero and leave the number in the first decimal place the way it is.

      For example, we want to estimate 0.28 to one decimal place. Because the second decimal placed number is greater than 5, we will add 1 to 3 and make 8 zero to get; 0.3

Now, if a number is x and it increased by 25%, then the new number is;

(125/100)x = (5/4)x

Since the denominator is 4, let us try decimal multiples of 4;

Let us try x = 0.12 since we are dealing with approximation to one decimal place

Approximating to one decimal place gives;

x_new = 0.1

0.1 is a decrease and not a 25% increase and so cannot be the number

Let us try x = 0.16

Approximating to one decimal place gives;

x_new = 0.2

%increase = (0.2 - 0.16)/0.16 × 100% = 25%

Thus, in conclusion, the value of the original number is 0.16.

Read more at; https://brainly.com/question/17028233

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