chaveslizzy
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

3x+4y=29
6x+5y=43
Solve through elimination

Sagot :

rosa6189

Answer:

Let's solve your system by elimination.

3x+4y=29;6x+5y=43

Multiply the first equation by -2,and multiply the second equation by 1.

−2(3x+4y=29)

1(6x+5y=43)

Becomes:

−6x−8y=−58

6x+5y=43

Add these equations to eliminate x:

−3y=−15

Then solve−3y=−15for y:

−3y=−15

−3y −3 = −15

−3

(Divide both sides by -3)

y=5

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

3x+4y=29

Substitute5foryin3x+4y=29:

3x+(4)(5)=29

3x+20=29(Simplify both sides of the equation)

3x+20+−20=29+−20(Add -20 to both sides)

3x=9

3x 3 = 9

3

(Divide both sides by 3)

x=3

Answer:

x=3 and y=5

Step-by-step explanation:

I love this stuff 229 999 0523

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.