scarletthaven
Answered

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an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

Sagot :

  • Total distance=150m-65m=85m
  • Time=5s

[tex]\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Distance}{Total\:Time}[/tex]

[tex]\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}[/tex]

[tex]\\ \rm\longrightarrow Avg\:Velocity= 17m/s[/tex]

spammingallowed

Answer:

[tex]displacement = 150 - 65 = 85m \\ time = 5sec \\ velocity = \frac{displacement}{time} \\ = \frac{85}{5} = 17 \frac{m}{s} south \\ thank \: you[/tex]

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