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cosA/1+sinA=(cotA/2-1)/(cotA/2+1)​

Sagot :

Answer:

[tex]\frac{1+sinA}{cosA}=\frac{\frac{cotA}{2}-1 }{\frac{cotA}{2}+1 } \\\\<=>(1+sinA)(\frac{cotA}{2}+1)=(\frac{cotA}{2}-1)cosA\\\\<=>\frac{cotA}{2}+\frac{cosA}{2}+1+sinA=\frac{cosA.cotA}{2}-cosA\\\\[/tex]

=> 2 sides cant be equal

Step-by-step explanation: