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Sagot :
Treasury bond's invested amount is "$7000" and Bond's invested amount is "$10000",
Let,
- The amount invested in treasury note will be = x
- The amount invested in bond will be = (x + 3000)
then,
→ [tex]\frac{x\times 4\times 3.8}{100} +\frac{(3000+x)\times 9\times 4.6}{100}=5204[/tex]
→ [tex]\frac{15.2x}{100}+\frac{(3000+x)\times 41.4}{100} =5204[/tex]
→ [tex]\frac{15.2x}{100} +\frac{124200+41.4x}{100} =5204[/tex]
→ [tex]\frac{15.2 x+124200+41.4x}{100} = 5204[/tex]
→ [tex]56.6x+124200=520400[/tex]
→ [tex]56.6x=520400-124200[/tex]
→ [tex]56.6x=396200[/tex]
→ [tex]x = \frac{396200}{56.6}[/tex]
→ [tex]= 7000[/tex]
Amount invested in bond will be:
= [tex]x+3000[/tex]
= [tex]7000+3000[/tex]
= [tex]10000[/tex]
Thus the above is the correct answer.
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