Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Using equivalent angles, the equivalent expression is:
[tex]-\sin{\frac{\pi}{12}}[/tex]
--------------------
- Angles between 0 and 90º(0 and 0.5π) are in the first quadrant.
- Angles between 90º and 180º(0.5π and π) are in the second quadrant.
- Angles between 180º and 270º(π and 1.5π) are in the third quadrant.
- Angles between 270º and 360º(1.5π and 2π) are in the fourth quadrant.
- Each angle will have equivalents in other quadrants.
--------------------
- The expression given is: [tex]\sin{\frac{13\pi}{12}}[/tex].
- The angle [tex]\frac{13\pi}{12}[/tex] is in the third quadrant.
- To find the equivalent angle in the first quadrant, for an angle in the third quadrant, 180º = π is subtracted from the angle.
Then:
[tex]\frac{13\pi}{12} - \pi = \frac{13\pi}{12} - \frac{12\pi}{12} = \frac{\pi}{12}[/tex]
The equivalent expression is, considering that in the third quadrant and in the first quadrant, the sine has opposite signals.
[tex]-\sin{\frac{\pi}{12}}[/tex]
A similar problem is given at https://brainly.com/question/23843479
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
