Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Write -2+2i in polar form (ans in degrees)

Sagot :

Answer:

2sqrt(2)cis(135)

2sqrt(2)e^(135i)

2sqrt(2)[cos(135)+isin(135)]

Step-by-step explanation:

The number is in form x+yi.

If x=y or x=-y, then we know we will need an angle measurement that is a multiple of 45 degrees; more accurately of the form (2k+1)45 degeees where k is an integer.

Since x is negative and y is positive, we are in the second quadrant. That means theta is 45(3) or 135 degrees.

At 135 degrees, we have the point

(-sqrt(2)/2,sqrt(2)/2). (Notice that x=-y).

-2+2i

Factor out 2:

2(-1+1i)

Multiply by 1 so that we can use the point mention. Namely, 2/sqrt(2) × sqrt(2)/2:

2 ×2/sqrt(2) (-sqrt(2)/2+sqrt(2)/2 i)

Simplify:

4/sqrt(2) (-sqrt(2)/2+sqrt(2)/2 i)

Continue to simplify:

4sqrt(2)/2 (-sqrt(2)/2+sqrt(2)/2 i)

Simplifying:

2sqrt(2)(-sqrt(2)/2+sqrt(2)/2 i)

Polar form is therefore

2sqrt(2)cis(135)

Or

2sqrt(2)e^(135i)

I don't know your exact desired polar form.

Could also be

2sqrt(2)[cos(135)+isin(135)].