485581
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Please answer question #2 and please show work

Please Answer Question 2 And Please Show Work class=

Sagot :

sqdancefan

9514 1404 393

Answer:

  2a. (360x +495)/(8x +11) = 45

  2b. 2((8x+11) +45) = 16x +112

Step-by-step explanation:

a) The area is the product of length and width.

  A = LW

We are given ...

  W = 8x +11

  A = 360x +495

The value of length can be found by solving for L:

  L = A/W

  L = (360x +495)/(8x +11)

The long-division solution to this is shown in the attachment.

  L = 45 . . . . simplified expression for length

__

b) The perimeter of the tank is twice the sum of length and width:

  P = 2(L +W)

Substituting the values for L and W, this is ..

  P = 2(45 +(8x +11)) . . . . expression for length of edge seal

  P = 2(8x +56)

  P = 16x + 112 . . . . . . simplified expression for seal length

View image sqdancefan
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.