Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The question is solved using the equations of motion
According to the equations of motion:
[tex]v^2 = u^2 -2gh[/tex]
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Note that at the maximum height, the final velocity (v) = 0 m/s
so we can write:
[tex]u^2 = 2gh[/tex]
[tex]h = \frac{u^2}{2gh}[/tex][tex]h= \frac{100^2}{2 * 10}[/tex]
h = 500 m
The time taken is obtained from:
[tex]v= u - gt[/tex]
since v= 0 at maximum height
[tex]u = gt\\\\t= u/g\\\\t= 100/10\\t = 10 s[/tex]
For more about equations of motion, see
https://brainly.com/question/20594939
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.