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I NEED HELP WITH THIS!! 50 POINTS!!!

Drag each system of equations to the correct location on the table.
Classify each system of equations as having a single solution, no solution, or infinite solutions.

I NEED HELP WITH THIS 50 POINTS Drag Each System Of Equations To The Correct Location On The Table Classify Each System Of Equations As Having A Single Solution class=

Sagot :

Answer:

Part 1) we have

----> equation A

Isolate the variable y

----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 2) we have

isolate the variable y

-----> equation A

isolate the variable y

 ----> equation B

Compare equation A and equation B

The slopes are equal

The y-intercept are different

That means

we have parallel lines with different y-intercept

so

The lines don't intersect

therefore

The system has no solution

Part 3) we have

isolate the variable y

-----> equation A

isolate the variable y

 ----> equation B

Compare equation A and equation B

The  equations are identical

That means

Is the same line

so

The system has infinitely solutions

Part 4) we have

isolate the variable y

-----> equation A

isolate the variable y

 ----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 5) we have

isolate the variable y

-----> equation A

isolate the variable y

 ----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 6) we have

isolate the variable y

-----> equation A

isolate the variable y

 ----> equation B

Compare equation A and equation B

The slopes are equal

The y-intercept are different

That means

we have parallel lines with different y-intercept

so

The lines don't intersect

therefore

The system has no solution

Step-by-step explanation:

View image canehnguyen80
plasticpinktrees

Answer:

Starting with the first one, we need to convert both of the equations into slope-intercept form. y = -2x + 5 is already in that form, now we just need to do it to 4x + 2y = 10.

2y = -4x + 10

y = -2x +5

Since both equations give the same line, the first one has infinite solutions.

Now onto the second one. Once again, the first step is to convert both of the equations into slope-intercept form.  

x = 26 - 3y becomes

3y = -x + 26

y = -1/3x + 26/3  

2x + 6y = 22 becomes

6y = -2x + 22

y = -1/3 x + 22/6

Since the slopes of these two lines are the same, that means that they are parallel, meaning that this one has no solutions.  

Now the third one. We do the same steps.  

5x + 4y = 6 becomes

4y = -5x + 6

y = -5/4x + 1.5

 

10x - 2y = 7 becomes

2y = 10x - 7

y = 5x - 3.5

Since these two equations are completely different, that means that this system has one solution.

Now the fourth one. We do the same steps again.  

x + 2y = 3 becomes

2y = -x + 3

y = -0.5x + 1.5

4x + 8y = 15 becomes

8y = -4x + 15

y = -1/2x + 15/8

Once again, since these two lines have the same slopes, that means that they are parallel, meaning that this one has no solutions.  

Now the fifth one.  

3x + 4y = 17 becomes

4y = -3x + 17

y = -3/4x + 17/4

-6x = 10y - 39 becomes

10y = -6x + 39

y = -3/5x + 3.9

Since these equations are completely different, there is a single solution.  

Last one!

x + 5y = 24 becomes

5y = -x + 24

y = -1/5x + 24/5

5x = 12 - y becomes

y = -5x +12

Since these equations are completely different, this system has a single solution.

Step-by-step explanation:

hope this helps you out:)

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