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The graph of a linear relation passes through the point (-2,7) and has a slope of 1/6.
Determine an equation for this linear relation in slope intercept form.

Sagot :

Answer:

Step-by-step explanation:

eq. of any line withslope 1/6 is

y=1/6x+c

∵ it passes through (-2,7)

so 7=1/6(-2)+c

c=7+1/3=22/3

eq. of line is

y=1/6x+22/3

wegnerkolmp2741o

Answer:

y = 1/6x + 7 1/3

Step-by-step explanation:

Slope intercept form is y=mx+b where m is the slope and b is the y intercept

y = 1/6x+b

Substitute the point into the equation

7 = 1/6(-2)+b

7 = -1/3+b

Add 1/3 to each side

7 1/3 = b

y = 1/6x + 7 1/3

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