Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Suppose you are conducting a study about how the average US worker spends time over the course of a workday. You are interested in how much time workers spend per day on personal calls, emails, and social networking websites, as well as how much time they spend socializing with coworkers versus actually working.

The most recent census provides data for the entire population Of U.S. workers on variables such as travel time to work, time spent at work, and break time at work. The census, however, does not include data on the variables you are interested in, so you obtain a random sample of 82 full-time workers in the United States and ask about personal calls, e-mails, and so forth. You are curious about how your sample compares with the census, so you also ask the workers the same questions about work that are asked in the census.

Suppose the mean break time per day from the most recent census is 29.6 minutes, with a standard deviation of 16.0 minutes. Your sample of 82 U.S. workers provides a mean break time per day of 31.9 minutes with a sample standard deviation of 22.4 minutes.

Organize this information by completing the following table.

μ = _________ M= __________
σ= _________ s= ___________
σM = _______ sM = _________

Sagot :

radhasharma6023

Answer:

lol

Step-by-step explanation:

Now don't get us wrong – not all of these answers raise this excellent question

The value of [tex]\mu[/tex] = 29.6, M = 31.9, [tex]\sigma[/tex] = 16 , s = 22.4, [tex]\sigma_m[/tex] = 3.121, and [tex]\rm S_m[/tex] = 2.473.

It is given that the mean break time per day from the most recent census is 29.6 minutes with a standard deviation of 16 minutes.

It is required to organize the information in a table if the sample size is 82.

What is the margin of error(MOE)?

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

[tex]\rm MOE = Z_{score}\frac{s}{\sqrt[]{n} }[/tex]

Where    is the z score at the confidence interval

            s is the standard deviation

            n is the number of samples.

We know:

[tex]\rm \sigma_m= \frac{\sigma^2}{n}[/tex]

We have,

[tex]\rm \sigma = 16 \ and \ n = 82[/tex]

[tex]\rm \sigma_m= \frac{16^2}{82}[/tex]

[tex]\rm \sigma_m= 3.121[/tex]

For [tex]\rm S_m[/tex]

[tex]\rm S_m = \frac{s}{\sqrt{n} }[/tex]

We have,

s = 22.4 and n = 82

[tex]\rm S_m = \frac{22.4}{\sqrt{82} }[/tex]

[tex]\rm S_m = 2.473[/tex]

Thus, the value of [tex]\mu[/tex] = 29.6, M = 31.9, [tex]\sigma[/tex] = 16 , s = 22.4, [tex]\sigma_m[/tex] = 3.121, and [tex]\rm S_m[/tex] = 2.473.

Learn more about the Margin of error here:

brainly.com/question/13990500

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.