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Solve for
x. Round to the nearest tenth of a degree, if necessary.


Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

Answer:

[tex]\displaystyle x \approx 30.8[/tex]

Step-by-step explanation:

Note that the figure is a right triangle, and that we are given the length of the side adjacent to x and the hypotenuse of the triangle.

Therefore, we can use the cosine ratio. Recall that:

[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]

The adjacent side is 8.5 and the hypotenuse is 9.9. Therefore:

[tex]\displaystyle \cos x = \frac{8.5}{9.9}[/tex]

We can take the inverse cosine of both sides:

[tex]\displaystyle x = \cos^{-1} \frac{8.5}{9.9}[/tex]

Use a calculator. Hence:

[tex]\displaystyle x \approx 30.8[/tex]

30 is the answer get me