Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

PLEASE SHOW WORK - HELP FAST
100 POINTS

Which theorem/postulate can be used to prove ∆PQR ≅ ∆STU?
What is the perimeter of ∆PQR?


PLEASE SHOW WORK HELP FAST 100 POINTS Which Theorempostulate Can Be Used To Prove PQR STU What Is The Perimeter Of PQR class=

Sagot :

Answer:

SSS

∆PQR = 43

Step-by-step explanation:

The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.

9 + 6y + 5 + 14 = 9 + 8y +14

28 + 6y = 9 + 8y + 14

28 + 6y = 8y + 23

      -6y    -6y

--------------------------

  28 = 2y + 23

 -23           -23

---------------------

      5 = 2y

     ----   ----

      2      2  

  2.5  =   y

9 + 14 + 6(2.5) + 5

23 + 15 + 5

 23 + 20

     43

∆PQR = 43

msm555

Answer:

Solution given:

In ∆ PQR and ∆ STQ

PQ=ST=9ft given

<Q=<T given

QR=TU = 14ft [given]

S.A.S axiom therom is used to prove

∆PQR ≅ ∆STU

Since ∆PQR ≅ ∆STU

their corresponding side is equal.so

6y+5=8y

5=8y-6y

2y=5

y=5/2

now

perimeter of ∆ PQR=sum of all sides

=9ft +14ft+ 6*5/2+5=43ft