Answered

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The town administrators separate the 84 houses in a neighborhood into equal
groups to do safety inspections. Which of the following groupings is not
possible?
F. Three groups of 26 houses H. Six groups of 14 houses
G. Four groups of 21 houses I. Seven groups of 12 houses

Sagot :

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Answer:

Step-by-step explanation:

F:  3×26 = 78 ≠ 84

G:  4×21 = 84

H:  6×14 = 84

I:  7×12 = 84

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