At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

mean is 1250
variance is 120
finding the probability between 970 and 1320
[tex] find p{970 < x < 1320}[/tex]


Sagot :

Although you said the variance is 120, I suspect you meant to say standard deviation. If that's the case, then

P(970 < x < 1320)

= P((970 - 1250)/120 < (x - 1250)/120 < (1320 - 1250)/120)

≈ P(-2.3333 < z < 0.5833)

= P(z < 0.5833) - P(z < -2.3333)

≈ 0.72012 - 0.009815

0.7104

If you really did mean variance, then

P(970 < x < 1320)

= P((970 - 1250)/√120 < (x - 1250)/√120 < (1320 - 1250)/√120)

≈ P(-25.5604 < z < 6.3901)

= P(z < 6.3901) - P(z < -25.5604)

≈ 1 - 0

≈ 1

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.