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Sagot :
Step-by-step explanation:
Find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first.
let the consecutive odd integers are :- x , x + 2 and x + 4.
According to question :-
the sum of the last two is 15 less than 5 times the first.
It means that
the sum of ( x + 2 ) and ( x + 4 ) is 15 less than 5 times the x .
( x + 2 ) + ( x + 4 ) = 5x - 15
x + 2 + x + 4 = 5x - 15
2x + 6 = 5x - 15
6 + 15 = 5x + 2x
21 = 7x
or ;
7x = 21
x = 21 / 7
x = 3
So, the consecutive odd numbers are :-
x = 3
x + 2 = 3 + 2 = 5
x + 4 = 3 + 4 = 7
=> 3 , 5 and 7
hope this helps you
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