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누가 좀 도와주세요 help
[tex] \sin(36) - \cos(54) \\ \tan(80) - \cot(10) [/tex]
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Sagot :

devishri1977

Answer:

Step-by-step explanation:

Sin (90 - ∅) = Cos ∅

90 -54 = 36

Sin 36 = Sin (90 - 54)

            = Cos 54      --------->(I)

Now, Sin (36) - Cos (54) = Cos 54 - Cos 54   {From 1}

                                        = 0

2) tan (90-∅) = Cot ∅

Tan 80 = Tan (90 - 10)

            = Cot 10  ----------(II)

Tan 80 - Cot 10 = Cot 10 - cot 10   -----------(from (II)}

                         = 0

ojasvijamkar

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