Answered

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PLease help and explain

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Sagot :

  • 4x+3y=23----(1)
  • x-5y=0----(2)

From eq(2)

[tex]\\ \sf\longmapsto x-5y=0[/tex]

[tex]\\ \sf\longmapsto x=5y\dots(3)[/tex]

  • Put the value in eq(1)

[tex]\\ \sf\longmapsto 4x+3y=23[/tex]

[tex]\\ \sf\longmapsto 4(5y)+3y=23[/tex]

[tex]\\ \sf\longmapsto 20y+3y=23[/tex]

[tex]\\ \sf\longmapsto 23y=23[/tex]

[tex]\\ \sf\longmapsto y=1[/tex]

  • Put the value in eq(3)

[tex]\\ \sf\longmapsto x=5y[/tex]

[tex]\\ \sf\longmapsto x=5(1)[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Hence

(x,y)=(5,1)

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