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Use the ideal gas law, PV=nRT to solve. R=0.0821
If I have 15 moles of gas at a temperature of 299K and a volume of 92L, what is the pressure of the gas?

Sagot :

lublana

Answer:

The pressure of the gas=4.002 atm

Explanation:

We are given that

R=0.0821

Number of moles, n=15

Temperature, T=299 K

Volume of gas, V=92 L

We have to find the pressure of the gas.

[tex]PV=nRT[/tex]

Substitute the values

[tex]P\times 92=15\times 0.0821\times 299[/tex]

[tex]P=\frac{15\times 0.0821\times 299}{92}[/tex]

[tex]P=4.002 atm[/tex]

Hence, the pressure of the gas=4.002 atm

chase1posey410

Answer:

According to the ideal gas law equation,

PV = nRT               (here, P = 5.5 atm, V = 10L, T = 298K, R = 0.0821 atmL/mol K)

or, n = RT/PV = (0.0821 X 298)/(5.5 X 10) = 0.44 moles of He gas

Explanation:

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