Answer:
f is not a function
Step-by-step explanation:
Given
Domain: Whole numbers
Range: Real numbers
Required
Is f a function
Base on the given parameters, f is not a function because:
There are more real numbers than whole numbers
And this implies that at least one element in the domain will have more than one corresponding elements in the range. i.e. one-to-many or many-to-many relationship
For a relation to be regarded as a function, the relationship has to be one-to-one or many-to-one
i.e. 1 or many domain elements to 1 element in the range.
An example is:
[tex]\begin{array}{ccccc}x & {1} & {9} & {9} & {0} \ \\ f(x) & {1.5} & {3.2} & {-3.5} & {0.1} \ \end{array}[/tex]
In the above function
The domain (i.e. x values) are whole numbers
The range (i.e. y values) are real numbers
However,
9 points to 3.2 and -3.5
So, the relation is not a function.
