Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
a) θ = 11 rad, θ = 1.75 rev., b) w = 9 rad / s, c) θ = 7.17 rev
Explanation:
This is a rotation kinematics exercise
θ = θ₀ + w₀ t + ½ α t²
They indicate the initial angular velocity w₀ = 2.00 rad / s, the angular acceleration α = 3.50 rad / s² and that at the initial instant θ₀ = 0
a) let's find the rotated angle
θ = 0 + 2.00 2.00 +1/2 3.5 2²
θ = 11 rad
let's reduce 2π rad = 1 rev
θ = 11 rad (1 rev / 2π rad)
θ = 1.75 rev.
b) angular velocity
w = w₀ + α t
w = 2.00 + 3.50 2
w = 9 rad / s
c) the angular displacement to reach this speed
w² = w₀² + 2 α θ
in this case they indicate that w = 2 9 = 18 rad / s
θ = [tex]\frac{w^2 - w_o^2}{2 \alpha }[/tex]
θ = [tex]\frac{18^2 - 2^2 }{2 \ 3.5 }[/tex]
θ = 45.7 rad
let's reduce to rev
θ = 45.7 rad (1rev / 2π rad)
θ = 7.17 rev
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
