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A random sample of 64 door-to-door encyclopedia salespersons were asked how long on average they were able to talk to the potential customer. Their answers revealed a mean of 8.5 minutes. The population standard deviation is 3 minutes.
Construct a 95% confidence interval for mu, the time it takes an encyclopedia salesperson to talk to a potential customer.
What is the upper confidence limit?


Sagot :

Answer:

The 95% confidence interval for mu, the time it takes an encyclopedia salesperson to talk to a potential customer is between 7.765 minutes and 9.235 minutes.

The upper confidence limit is of 9.12 minutes.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{3}{\sqrt{64}} = 0.735[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 8.5 - 0.735 = 7.765 minutes

The upper end of the interval is the sample mean added to M. So it is 8.5 + 0.735 = 9.235 minutes

The 95% confidence interval for mu, the time it takes an encyclopedia salesperson to talk to a potential customer is between 7.765 minutes and 9.235 minutes.

What is the upper confidence limit?

Similar procedue above, just a few changes.

Now Z with a p-value of 0.95, so Z = 1.645.

[tex]M = 1.645\frac{3}{\sqrt{64}} = 0.62[/tex]

8.5 + 0.62 = 9.12 minutes

The upper confidence limit is of 9.12 minutes.

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