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Determine S9 of the series where a = 6 and r = 2. Provide a complete solution

Sagot :

chibunduoyibe

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my answer is in the image above

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kamilmatematik100504

if it is an arithmetic progression

[tex]\displaystyle\bf \boxed{S_n=\frac{a_1+a_n}{2} \cdot n\quad; \quad a_n=a_1+(n-1)r}\\\\\\S_9=\frac{6+6+16}{2} \cdot9=126\\\\\\Answer: \boxed{S_9=126}[/tex]                                                                 if it is a geometric progression                                                                              [tex]\displaystyle\bf \boxed{ S_n=\frac{a_1(1-r^n)}{1-r} \quad }\\\\\\S_9=\frac{6(1-2^9)}{1-2} =511\cdot6=3066\\\\\\Answer:\boxed{ S_9=3066}[/tex]                                                                                                  

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