NateTheGreat0929
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What is the rule for the following geometric sequence? 64,128,256,512...
a) a_(n) = 64(-2)^n-1
b) a_(n) = 64(2)^n-1
c) a_(n) = 64(1/2)^n-1
d) a_(n) = 64(-1/2)^n-1

Sagot :

Answer:

B

Step-by-step explanation:

The explicit rule for a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{128}{64}[/tex] = 2 , then

[tex]a_{n}[/tex] = 64 [tex](2)^{n-1}[/tex] → B

Answer:

b).

[tex]{ \tt{a _{n} = a( {r}^{n - 1} )}} \\ { \tt{a _{n} = 64( {2}^{n - 1}) }}[/tex]

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.