KanaKittyKat
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heya kitties. graph y−5=43(x−5)

coordinates plz

Sagot :

Given:

The equation is:

[tex]y-5=\dfrac{4}{3}(x-5)[/tex]

To find:

The graph of the given equation.

Solution:

Point slope form of a line is:

[tex]y-y_1=m(x-x_1)[/tex]               ...(i)

We have,

[tex]y-5=\dfrac{4}{3}(x-5)[/tex]           ...(ii)

On comparing (i) and (ii), we get

[tex]x_1=5,y_1=5,m=\dfrac{4}{3}[/tex]

It means, slope of the line is [tex]\dfrac{4}{3}[/tex] and it passes through the point (5,5).

Putting x=2 in the given equation, we get

[tex]y-5=\dfrac{4}{3}(2-5)[/tex]

[tex]y=\dfrac{4}{3}(-3)+5[/tex]

[tex]y=-4+5[/tex]

[tex]y=1[/tex]

The line passes through the point (2,1).  Plot the points (2,1) and (5,5) on a coordinate plane and connect them by a free hand curve as shown below.

View image erinna
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