Answer:
The probability of observing between 43 and 64 successes=0.93132
Step-by-step explanation:
We are given that
n=100
p=0.50
We have to find the probability of observing between 43 and 64 successes.
Let X be the random variable which represent the success of population.
It follows binomial distribution .
Therefore,
Mean,[tex]\mu=np=100\times 0.50=50[/tex]
Standard deviation , [tex]\sigma=\sqrt{np(1-p)}[/tex]
[tex]\sigma=\sqrt{100\times 0.50(1-0.50)][/tex]
[tex]\sigma=5[/tex]
Now,
[tex]P(43\leq x\leq 64)=P(42.5\leq x\leq 64.5)[/tex]
[tex]P(42.5\leq x\leq 64.5)=P(\frac{42.5-50}{5}\leq Z\leq \frac{64.5-50}{5})[/tex]
[tex]=P(-1.5\leq Z\leq 2.9)[/tex]
[tex]P(42.5\leq x\leq 64.5)=P(Z\leq 2.9)-P(Z\leq- 1.5)[/tex]
[tex]P(42.5\leq x\leq 64.5)=0.99813-0.06681[/tex]
[tex]P(43\leq x\leq 64)=0.93132[/tex]
Hence, the probability of observing between 43 and 64 successes=0.93132
