If a window is to be 6 feet wide, how high should it be, to the nearest tenth of a foot, to be a golden rectangle

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02-07-2021
Mathematics

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If a window is to be 6 feet wide, how high should it be, to the nearest tenth of a foot, to be a golden rectangle

Sagot :

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ewomazinoade ewomazinoade · Answer 1 · 2021-07-03T14:37:40-04:00

Answer:

3.7 feet

Step-by-step explanation:

A golden rectangle is a rectangle in which the length and the width are in the ratio 1 : 1.618

If the width of the rectangle is 6, the length = 6 / 1.618 = 3.708 ft

= 3.7 (to the nearest tenth)

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

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