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[tex]factorise \: \\ \\ r {}^{2} - 10r + 21[/tex]


Sagot :

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (r - 7)(r - 3) }}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

[tex] {r}^{2} - 10r + 21[/tex]

[tex] = {r}^{2} - 7r - 3r + 21[/tex]

Taking [tex]r[/tex] as common from first two terms and [tex]3[/tex] from last two terms, we have

[tex] = r(r - 7) - 3(r - 7)[/tex]

Taking the factor [tex](x-7)[/tex] as common,

[tex] = (r - 7)(r - 3)[/tex]

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

Step-by-step explanation:

Your Answer with

Explanation is given in the attachment

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