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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 5?

Select one:
a. 420
4
20


b. 320
3
20


c. 520
5
20


d. 120
1
20



Sagot :

fichoh

Answer:

4 / 20 = 1/5

Step-by-step explanation:

Given that:

Ticket numbering is from 1 - 20

Hence, total possible number of tickets : (1, 2, 3, 4, 5, 6, 7, 8,9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20)

Total possible outcomes = 20

Required outcome = multiples of 5 ; the multiples of 5 from the entire ticket numbers are : 5, 10, 15, 20

Required outcome = 4

P(multiple of 5) = Required outcome / Total possible outcomes

P(multiple of 5) = 4 / 20 = 1 / 5

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