stumpidhead
Answered

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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and point Z is at (5, 5).
What is the perimeter of rhombus WXYZ?

StartRoot 13 EndRoot units
12 units
StartRoot 13 EndRoot units
20 units

Sagot :

MrRoyal

Answer:

[tex]P = 4\sqrt{13}[/tex]

Step-by-step explanation:

Given

[tex]W = (7, 2)[/tex]

[tex]X = (5, -1)[/tex]

[tex]Y = (3, 2)[/tex]

[tex]Z =(5, 5)[/tex]

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2[/tex]

So, we have:

[tex]WX = \sqrt{(5- 7)^2 + (-1 - 2)^2[/tex]

[tex]WX = \sqrt{13}[/tex]

[tex]XY = \sqrt{(3-5)^2 + (2--1)^2}[/tex]

[tex]XY = \sqrt{13}[/tex]

[tex]YZ = \sqrt{(5-3)^2 + (5-2)^2}[/tex]

[tex]YZ = \sqrt{13}[/tex]

[tex]ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}[/tex]

[tex]ZW = \sqrt{13}[/tex]

The perimeter is:

[tex]P = WX + XY + YZ + ZW[/tex]

[tex]P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}[/tex]

[tex]P = 4\sqrt{13}[/tex]

Answer:

C on edge 2021

Step-by-step explanation:

I took the cumulative exam

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