Answered

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the principal argument of z = —4+i4√3 is​

Sagot :

mdakbarpasha55

Answer:

Let z=−4+0i. Then, ∣z∣=

(−4)

2

+0

=4

Clearly, the point (−4,0) representing z=−4+0i lies on the negative side of real axis. Therefore, principal argument of z is π.

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