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Sagot :
Answer: A $6
Step-by-step explanation:
Let x = price per child ticket, y= price per senior ticket.
As per given, we have
5x+12y=102 (i)
12x+14y=156 (ii)
From (i), we have
[tex]x=\dfrac{102-12y}{5}[/tex] (iii)
Put value of x in (ii), we get
[tex]12(\dfrac{102-12y}{5})+14y=156\\\\\\ \dfrac{1224-74y}{5}=156\\\\\\1224-74y=5\times156\\\\\\ 1224-74y=780\\\\\\ 74y=1224-780\\\\\\ 74y=444\\\\ y=\dfrac{444}{74}\\\\\\ y=6[/tex]
Hence, the price of senior ticket = $6
Thus the correct option is A.
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