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Find the Laplace Transform of the following function.

f(t) = 10 cos (12t+ 60°) u(t)

Sagot :

batolisis

Answer:

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Step-by-step explanation:

f ( t ) = 10 cos ( 12t + 60°) u(t)

attached below is a detailed solution of the given problem

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

View image batolisis
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