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Sagot :
Answer:
[tex]area = \pi {( \frac{d}{2}) }^{2} \\ = 3.14 \times {22}^{2} \div 4 \\ = 379.94 \: {yd}^{2} [/tex]
Answer:
150.72² yds
Step-by-step explanation:
We know that they want a 2 yd around the whole pool. We also know that the diameter is 22yds (the raidus is therefore 11 yds). We can solve this by first finding the area of the pool.
3.14 × 11² = 379.94
Now we can solve for the area of the circle, with the 2 yd path around the whole pool. We can do this by adding 2 yds to our radius.
3.14 × 13² = 530.66
Now our final step is to subtract the area of the pool from the area of the entire circle.
530.66 - 379.94 = 150.72
Therefore, the area of the walk is equal to 150.72 yds²
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