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A sled is moving down a steep hill in a straight line. At time ts, the
acceleration of the sled is ams-2 where a = 1/500(20t^2-t^3), 0 < t < 20. When t = 0
the sled is at rest at the top of the hill. Find the distance the sled travels in
the first 10 s of its motion.

Sagot :

MrRoyal

Acceleration is the rate of change of velocity over time

The sled travels 100 meters in the first 10 seconds of its motion

How to determine the distance

The acceleration function is given as:

[tex]a = \frac 1{500}(20t^2 - t^3)[/tex]

When t = 10, we have:

[tex]a = \frac 1{500}(20*10^2 - 10^3)[/tex]

[tex]a = 2[/tex]

The distance at 10 seconds is then calculated as;

[tex]S = ut +\frac 12 at^2[/tex]

Where:

u = initial velocity = 0

So, we have:

[tex]S = 0 *10 +\frac 12 * 2 * 10^2[/tex]

[tex]S =100[/tex]

Hence, the sled travels 100 meters in the first 10 seconds of its motion

Read more about acceleration at:

https://brainly.com/question/605631

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