Answered

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cotA + tanA= secAcosecA

Sagot :

okpratikshaok57

Step-by-step explanation:

cotA + tanA

= cosA / sinA+ sinA/ cosA

= cos2A + sin2A / sinA* cosA

= 1 / sinA* cosA

=1/ sinA * 1/ cosA

= cosecA *secA

=secAcosecA

bhadelsimron19

[tex]\frac{cos^2A + sin^2A}{sinAcosA}[/tex]Answer:

Step-by-step explanation:

cotA + tanA = secAcosecA

LHS=cotA + tanA

=[tex]\frac{cosA}{sinA}[/tex] + [tex]\frac{sinA}{cosA}[/tex]

take lcm of the denominator

=[tex]\frac{cosA*cosA + sinA*sinA}{sinAcosA}[/tex](COS^2A + sin^2A =1)

=[tex]\frac{1}{sinAcosA}[/tex]

=1/sinA * 1/cosA

=cosecA*secA

=secAcosecA

therefore LHS=RHS

hence proved.

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