Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Volume of square based pyramid is 1568 cm3 and half of the length of the

side of the base is 7cm. Calculate the area of triangular faces of pyramid.
​

Sagot :

redgram

answer:

1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.