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Sagot :
Answer:
0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.
Step-by-step explanation:
Rain on November 1:
0.9 of 0.6(rain on Oct 31).
0.3 of 0.4(not rain on Oct 31).
Rain on November 2:
Considering rain on November 1, 0.9 probability of rain.
Rain on November 3:
Considering rain on November 2, 0.1 probability of rain.
Find the probability of rain on November 1 and 2, but not on November 3.
Multiplicating the probabilities:
[tex]p = (0.9*0.6+0.3*0.4)*0.9*0.1 = 0.0594[/tex]
0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.
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