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Sagot :
Answer:
Standard deviation = 12.8 Approx.
Step-by-step explanation:
Given series;
88, 65, 88, 49, 60, 71, 56, 87, 64, and 52.
Find:
Standard deviation
Computation:
Assume mean (a) = 60
x d(x - a) d²
88 28 784
65 5 25
88 28 784
49 -11 121
60 0 0
71 11 121
56 -4 16
87 27 729
64 4 16
52 -8 64
Σd = 80 Σd² = 2,660
So,
Standard deviation = √[Σd² / N] - [Σd / N]²
Standard deviation = √[2260 / 10] - [80 / 10]²
Standard deviation = √226 - 64
Standard deviation = √162
Standard deviation = 12.8 Approx.
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