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Special Right Triangles (Radical Answers)


Need Help NO LINKS Please Special Right Triangles Radical Answers class=

Sagot :

Answer:

x =  [tex]2\sqrt{2}[/tex] (or [tex]\frac{2\sqrt{2} }{1}[/tex] if it needs to be represented as a rational denominator)

Step-by-step explanation:

We know that;

1.) This triangle is equilateral, and because of the line segment it's divided into 2 right triangles.

2.) The base of the whole triangle would be 4, and the base of the right triangle would be 2, since the base is cut in half with a mid point.

Therefore we can say;

A² + B² = C²

x² + 2² = 4²

x² + 4 = 16

x² = 16 - 4

x² = 8

x = [tex]\sqrt{8}[/tex]

Simplifying this further would be;

[tex]\sqrt{8}[/tex] = [tex]\sqrt{4} * \sqrt{2}[/tex]

[tex]\sqrt{8}[/tex] = [tex]2\sqrt{2}[/tex] (or [tex]\frac{2\sqrt{2} }{1}[/tex] if it needs to be represented as a rational denominator)

Hope this helps!