Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Given the equation of a circle below, determine the center and radius of the circle.
(x+5)^2+y^2=36


Sagot :

9514 1404 393

Answer:

  • center: (-5, 0)
  • radius: 6

Step-by-step explanation:

Compare the given equation to the standard form equation for a circle with center (h, k) and radius r.

 (x -h)^2 +(y -k)^2 = r^2

You see that ...

 -h = +5   ⇒   h = -5

 -k = 0   ⇒   k = 0

  r^2 = 36   ⇒   r = √36 = 6

The center is (h, k) = (-5, 0), and the radius is r = 6.