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One leg of a right triangle is 1 cm longer than the other leg. The hypotenuse measures 5 cm.

Part A: Find the perimeter of the triangle.

Part B: Find the area of a triangle

Sagot :

Answer:

[tex]hypotenuse = 5 \: cm \\ height = 5 - 1 = 4 \: cm \\ base = \sqrt{ {5}^{2} - {4}^{2} } = \sqrt{9} = 3 \: cm[/tex]

Part A:

[tex]perimeter = 5 + 4 + 3 \\ = 12 \: cm[/tex]

Part B:

[tex]area = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 3 \times 4 \\ = 6 \: {cm}^{2} [/tex]

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