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Sagot :
Answer:
Coefficient of friction is [tex]0.068[/tex].
Work done is [tex]320~J[/tex].
Explanation:
Given:
Mass of the box ([tex]m[/tex]): [tex]60[/tex] kg
Force needed ([tex]F[/tex]): [tex]40[/tex] N
The formula to calculate the coefficient of friction between the floor and the box is given by
[tex]F=\mu mg...................(1)[/tex]
Here, [tex]\mu[/tex] is the coefficient of friction and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]40[/tex] N for [tex]F[/tex], [tex]60[/tex] kg for [tex]m[/tex] and [tex]9.80[/tex] m/s² for [tex]g[/tex] into equation (1) and solve to calculate the value of the coefficient of friction.
[tex]40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068[/tex]
The formula to calculate the work done in overcoming the friction is given by
[tex]W=Fd..........................(2)[/tex]
Here, [tex]W[/tex] is the work done and [tex]d[/tex] is the distance travelled.
Substitute [tex]40[/tex] N for [tex]F[/tex] and [tex]8 m[/tex] for [tex]d[/tex] into equation (2) to calculate the work done.
[tex]W=40~N\times8~m\\~~~~= 320~J[/tex]
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