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Solve for x. Then find the side lengths of the triangle. If needed, round to the nearest tenth of a foot.
(Check image)

Solve For X Then Find The Side Lengths Of The Triangle If Needed Round To The Nearest Tenth Of A Foot Check Image class=

Sagot :

whitneytr12

Answer:

The sides are:

[tex]s_{1}=3x=3(6.0)=18 \:ft[/tex]

[tex]s_{2}=6x=6(6.0)=36 \:ft[/tex]

Step-by-step explanation:

We have a right triangle, so we can use the Pythagoras theorem.

[tex]40^{2}=(6x)^{2}+(3x)^{2}[/tex]

Let's solve it for x.

[tex]40^{2}=36x^{2}+9x^{2}[/tex]

[tex]1600=45x^{2}[/tex]

[tex]x^{2}=35.56 \:ft^{2}[/tex]

[tex]x=6.0 \:ft[/tex]

Therefore, the lengths will be:

First side: [tex]s_{1}=3x=3(6.0)=18 \:ft[/tex]

Second side: [tex]s_{2}=6x=6(6.0)=36 \:ft[/tex]

I hope it helps you!

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