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What is the margin of error if the sample size is 100, sample mean is 68.0, and standard deviation is 4.0

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Answer:

Step-by-step explanation:

What is the margin of error if the sample size is 100, sample mean is 68.0, and standard deviation is 4.0

The Margin of error formula =

± z score × s/√n

Where s = standard deviation= 4

n= Number for samples = 100

z = z score of confidence interval

Margin of error = ± z × 4/√100

Margin of error = ±z × 4/10

=± z × 2/5

= ± z × 0.4

= ± 0.4z

Margin of error = ± 0.4z

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