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How many ways can six of the letters of the word palindrome be selected and written in a row where either the first two letters are PA(in order) or the last two letters are ME (in order)

Sagot :

Answer:

1680

Step-by-step explanation:

The given word is "PALINDROME".

The number of ways in [tex]$\text{which six of the letters of the word}$[/tex], "PALINDROME" be selected and is written in a row if the first two letters must be PA or the last two letters are ME is given by :

[tex]$^8C_4 \times 4! = 4 \times 7 \times 6 \times 5$[/tex]

              = 1680

Therefore, the word "PALINDROME" can be written in 1680 ways such that the first two letters are PA in a row or the last two letters are ME.

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