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Find the value of x, when log 10x + log 2 = log 60

Sagot :

wegnerkolmp2741o

Answer:

x = 3

Step-by-step explanation:

log 10x + log 2 = log 60

Subtract log 2 from each side

log 10x + log 2 -log 2 = log 60 - log 2

log 10x  = log 60 - log 2

We know  that log a - log b = log (a/b)

log 10 x = log (60/2)

log 10x  = log 30

We know log a = log b  that a = b

10x = 30

Divide by 10

10x/10 = 30/10

x =3

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