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The ship was travelling 93 meters per second, 25 degrees above the x-axis Northeast. Determine the magnitude and direction of the horizontal vector component, Vx.

Sagot :

Answer: [tex]92.18\ m/s[/tex], east

Explanation:

Given

Ship is traveling at a speed of [tex]v=93\ m/s[/tex]

Direction of ship is [tex]25^{\circ}[/tex] North of east

If we break velocity vector in x and y axes then, the horizontal component is given by

[tex]\Rightarrow v_x=93\cos 25^{\circ}\\\Rightarrow v_x=92.18\ m/s[/tex]

The direction of horizontal component is towards east with magnitude of [tex]92.18\ m/s[/tex]

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